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Mathematics

Radical and rational equations — ACT practice questions

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What this topic is

Radical and rational equations carry a special risk: solving them can produce answers that do not actually work.

Squaring both sides of an equation with a square root may introduce an extraneous solution, so every result needs to be checked in the original equation. Rational equations, which have variables in denominators, are usually cleared by multiplying through by a common denominator, but any value that makes a denominator zero must be rejected.

Work-rate problems, where two machines together finish a job, lead to rational equations because their rates, the reciprocals of their times, add. ACT Mathematics answer choices often include the extraneous value as a distractor.

Sample questions

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Question 1Easier

What is the solution of 3x+12=5x?

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Answer: C — 4

Subtracting 3x from both sides gives 2x=12, so x=4. The value 0 is excluded because it makes a denominator zero.

Question 2Mid

One pump fills a tank in x hours, and another pump fills the same tank in x+6 hours. Working together, the two pumps fill the tank in 4 hours. What is the value of x?

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Answer: B — 6

Clearing denominators gives x2−2x−24=0, so the candidates are 6 and −4. Because a completion time is positive, x=6.

Question 3Mid

What is the solution of 2x+15=x+3?

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Answer: C — −2+10

Squaring gives x2+4x−6=0, whose roots are −2±10. The smaller root makes x+3 negative, so only −2+10 works.

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