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Piecewise functions — ACT practice questions

Piecewise functions on the ACT Mathematics test are defined by different formulas on different intervals of the domain. Students must choose the correct piece for a given input, solve for x or a parameter, and check that any solution actually belongs to that interval. Items often ask for the input that produces a stated output, the constant that makes the function continuous at a breakpoint, or the value of a composition of two such functions. Answer choices are typically numbers. A common trap is using the wrong piece or keeping a root that falls outside its stated interval.

  • Section: Mathematics 45 questions on the paper
  • 45 practice questions in the app

Sample questions

Question 1

The function vv is defined by v(x)=2x+7v(x)=2x+7 when x1x\le -1 and v(x)=x2+4v(x)=x^2+4 when x>1x>-1. For what value of xx is v(x)=13v(x)=13?

  1. A-3
  2. B3
  3. C6
  4. D9
Show answer

Answer: B — 3

The linear branch gives x=3x=3, which does not satisfy x1x\le-1. The quadratic branch gives x=±3x=\pm3, but only x=3x=3 satisfies x>1x>-1.

Question 2

The function HH is defined by H(x)=cx5H(x)=cx-5 when x<3x<3 and H(x)=4x+cH(x)=4x+c when x3x\ge3. For what value of cc is HH continuous at x=3x=3?

  1. A72\dfrac{7}{2}
  2. B172\dfrac{17}{2}
  3. C232\dfrac{23}{2}
  4. D17
Show answer

Answer: B — 172\dfrac{17}{2}

Continuity requires the two branch expressions to agree at x=3x=3. Setting 3c5=12+c3c-5=12+c gives 2c=172c=17, so c=172c=\dfrac{17}{2}.

Question 3

The functions ff and gg are defined as follows.

f(x)=x+2f(x)=|x|+2 when x1x\le-1, and f(x)=x23f(x)=x^2-3 when x>1x>-1.

g(x)=2x1g(x)=2x-1 when x<6x<6, and g(x)=10xg(x)=10-x when x6x\ge6.

What is the value of f(g(2))f(g(2))?

  1. A-1
  2. B5
  3. C6
  4. D8
Show answer

Answer: C — 6

Because 2<62<6, g(2)=2(2)1=3g(2)=2(2)-1=3. Because 3>13>-1, f(3)=323=6f(3)=3^{2}-3=6.

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