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Mathematics

Piecewise functions — ACT practice questions

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What this topic is

Piecewise functions use different rules on different parts of the domain, so the first step is always deciding which rule applies to the given input.

For instance, if f(x) equals x plus one when x is negative and equals two times x when x is zero or positive, then f of negative four uses the first rule and f of three uses the second. Solving an equation means checking each rule separately and discarding solutions outside that rule's interval.

ACT Mathematics also asks for the value of a constant that makes the pieces meet, called continuity, and for composite values. Answer choices often reflect using the wrong piece.

Sample questions

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Question 1Mid

The function v is defined by v(x)=2x+7 when x≤−1 and v(x)=x2+4 when x>−1. For what value of x is v(x)=13?

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Answer: B — 3

The linear branch gives x=3, which does not satisfy x≤−1. The quadratic branch gives x=±3, but only x=3 satisfies x>−1.

Question 2Mid

The function H is defined by H(x)=cx−5 when x<3 and H(x)=4x+c when x≥3. For what value of c is H continuous at x=3?

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Answer: B — 172

Continuity requires the two branch expressions to agree at x=3. Setting 3c−5=12+c gives 2c=17, so c=172.

Question 3Mid

The functions f and g are defined as follows.

f(x)=∣x∣+2 when x≤−1, and f(x)=x2−3 when x>−1.

g(x)=2x−1 when x<6, and g(x)=10−x when x≥6.

What is the value of f(g(2))?

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Answer: C — 6

Because 2<6, g(2)=2(2)−1=3. Because 3>−1, f(3)=32−3=6.

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