Study on the flyISEE UpperMathematics AchievementRatios and proportions; distance-rate-time

Mathematics Achievement

Ratios and proportions; distance-rate-time — ISEE Upper practice questions

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What this topic is

Scale, rates and similar figures all belong to Ratios and proportions; distance-rate-time in Mathematics Achievement.

Similar figures follow a key rule: if side lengths are scaled by a factor, area is scaled by the square of that factor, so doubling every side makes the area four times larger, not twice. Work-rate problems are handled by finding the output of one worker or machine per hour, then scaling to the new number and time.

Equal-cost statements set up a proportion between two prices. Distance-rate-time items use distance equals rate times time, and units must agree before any calculation, such as converting minutes to hours.

Sample questions

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Question 1Mid

A triangle has side lengths 6, 8, and 10 and area 24 square units. A second triangle is similar to it, and the side corresponding to the side of length 8 has length 12. What is the area of the second triangle?

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Answer: C — 54

The side-length scale factor is 128=32. Areas scale by the square of the side-length scale factor, so the area scale factor is 94. The second triangle’s area is 24×94=54.

Question 2Easier

At a farmers market, seven sacks of rice cost the same as twenty-one sacks of flour. If one sack of flour costs $3, what is the price of one sack of rice?

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Answer: B — $9

Twenty-one sacks of flour cost 21×$3=$63, and that equals the cost of the 7 sacks of rice, so one sack of rice costs $63÷7=$9. (A) just copies the given flour price, while (C) and (D) apply the wrong sack ratio (treating it as 4:1 or 5:1 instead of 3:1).

Question 3Easier

5 identical machines produce 150 parts in 6 hours. At the same per-machine rate, how many parts will 7 machines produce in 6 hours?

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Answer: C — 210

Each machine produces 150÷(5⋅6)=5 parts per hour. Thus 7 machines produce 7(6)(5)=210 parts.

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